Pin pitch means how tiny the physical pins in the connector can be spaced apart.
IR drop losses happen because a wire has resistance, it isn’t a perfect conductor. 28AWG wire has about 0.22ohm/m. Given a 2 meter cable, you might expect to see 0.44ohm one-way. Current is also travelling back, so the circuit “sees” another 0.44ohm. That’s a total of 0.88ohm
A wire will cause voltage drop following ohm’s law. V=I/*R. So for 1A of current, you will see 0.88V lost.
Say you’re trying to charge at 15W (5V 3A), your phone is only going to ‘see’ 2.36 volts, and 7.9W are wasted in the cable.
For a 100W device (20V, 5A), 4.4V are lost, also meaning 22W are wasted.
(For others reading this, this is a perfect followup to my comment here explaining the “why”, while this is an excellent view into the “how” and picks up the bits I dropped about Ohms Law.)
Pin pitch means how tiny the physical pins in the connector can be spaced apart.
IR drop losses happen because a wire has resistance, it isn’t a perfect conductor. 28AWG wire has about 0.22ohm/m. Given a 2 meter cable, you might expect to see 0.44ohm one-way. Current is also travelling back, so the circuit “sees” another 0.44ohm. That’s a total of 0.88ohm
A wire will cause voltage drop following ohm’s law. V=I/*R. So for 1A of current, you will see 0.88V lost.
Say you’re trying to charge at 15W (5V 3A), your phone is only going to ‘see’ 2.36 volts, and 7.9W are wasted in the cable.
For a 100W device (20V, 5A), 4.4V are lost, also meaning 22W are wasted.
(For others reading this, this is a perfect followup to my comment here explaining the “why”, while this is an excellent view into the “how” and picks up the bits I dropped about Ohms Law.)